2y-3=y^2

Solution for 2y-3=y^2 equation:

Simplifying
2y + -3 = y2

Reorder the terms:
-3 + 2y = y2

Solving
-3 + 2y = y2

Solving for variable 'y'.

Combine like terms: y2 + -1y2 = 0
-3 + 2y + -1y2 = 0

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
3 + -2y + y2 = 0

Move the constant term to the right:

Add '-3' to each side of the equation.
3 + -2y + -3 + y2 = 0 + -3

Reorder the terms:
3 + -3 + -2y + y2 = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -2y + y2 = 0 + -3
-2y + y2 = 0 + -3

Combine like terms: 0 + -3 = -3
-2y + y2 = -3

The y term is -2y.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2y + 1 + y2 = -3 + 1

Reorder the terms:
1 + -2y + y2 = -3 + 1

Combine like terms: -3 + 1 = -2
1 + -2y + y2 = -2

Factor a perfect square on the left side:
(y + -1)(y + -1) = -2

Can't calculate square root of the right side.

The solution to this equation could not be determined.